16:40, 3 марта 2026Мир
Nothing in the argument required the arc to be a semicircle. If the arc has length xxx times the circumference (where x≤1/2x \leq 1/2x≤1/2), each anchor's event has probability xN−1x^{N-1}xN−1 instead of (1/2)N−1(1/2)^{N-1}(1/2)N−1. Mutual exclusivity still holds because the gap is at least 1−x≥1/21 - x \geq 1/21−x≥1/2 of the circumference, too large for any other anchor's arc to bridge:
，这一点在快连下载安装中也有详细论述
08:48, 4 марта 2026Экономика
阅星瞳 X4 的诞生，可以说是墨水屏「特化」的代表性。
Фото: VANTOR / Reuters